Substitute f=.008IPR, RE=.031 into the formulae. h=(.008)2÷(8×.031)×1000=.258µinch The theoretical finished surface roughness is .258µinch.

First, calculate the cutting length per min. from the feed and spindle speed. l=f×n=0.2×1000=200(mm/min) Substitute the answer above into the formula. Tc=lm÷l=100÷200=0.5(min) 0.5×60=30(sec)The answer is 30 sec.

※Divide by 1000 to change to m from mm. vc (m/min) : Cutting Speed Dm (mm) : Workpiece Diameter π (3.14) : Pi n (min-1) : Main Axis Spindle Speed

Cold Heading Dies Grade MD50A  100% virgin raw materials; Hip sintered, high hardness, high wear resistance; Grade Co Grain Size of WC Hardness Density Flexural Strength Bending Toughness Elastic Modulus Coefficient of Thermal Expansion Application % HRA HV30 g/cm3 MPa N/mm2 GPa 10-6/℃ MD51B 19 medium 85 940 13.5 3100 　 400 6.7 Suitable for mould of shrinkage rod with large reduction in diameter MD50A 20 medium 85.8 1020 13.4 3300 　 390 6.8 Suitable for mould of shrinkage rod with small reduction in diameter MD60A 20 medium 84 860 13.6 2900 　 390 6.8 Suitable for mould to make straight rod, screws,nut etc MD61B 22 medium 84 860 13.3 3150 　 360 7.1 Suitable for heavy hardness stainless steel MD62B 22 medium 83.5 820 13.3 3000 　 360 7.1 Suitable for dry wall screw and common stainless steel MD65A 25 medium 84.1 870 12.9 3100 　 340 7.6 Suitable for heavy loads straight rod moulds MD70A 25 medium 82.5 760 13.1 2800 　 340 7.6 Suitable for heavy loads nut moulds           D                                                            L ≤15 ＞15～30 ＞30～50 ＞50～80 ＞80                                                    Deviation ≤Ф15 ±0.20 ±0.30 ±0.40 　 　 ＞Ф15～30 ±0.30 ±0.40 ±0.50 ±0.60 　 ＞Ф30～50 ±0.50 ±0.60 ±0.70 ±0.75 ±0.80 ＞Ф50～80 　 ±0.70 ±0.88 ±0.90 ±1.0              d                                                              L ≤18 ＞18～30 ＞30～50 ＞50～80 ＞80 Deviation ≤Ф5 0～-0.40 0～-0.40 0～-0.4 0～-0.5 　 ＞Ф5～10 0～-0.50 0～-0.60 0～-0.70 0～-0.75 　 ＞Ф10～20 0～-0.70 0～-0.75 0～-0.80 0～-0.90 0～-1.00 ＞Ф20～35 　 0～-0.90 0～-1.00 0～-1.10 0～-1.20                                    L                                                                 D ≤Ф15 ＞Ф15～Ф30 ＞Ф30～Ф50 ＞Ф50～Ф80 Deviation ≤15 ï¹¢0.8 ï¹¢1.0 ï¹¢1.2 　 ï¹¢0.3 ï¹¢0.3 ï¹¢0.3 　 ＞15～30 ï¹¢1.0 ï¹¢1.2 ï¹¢1.5 ï¹¢1.6 ï¹¢0.3 ï¹¢0.3 ï¹¢0.3 ï¹¢0.4 ＞30～50 ï¹¢1.5 ï¹¢1.5 ï¹¢1.8 ï¹¢2.0 ï¹¢0.5 ï¹¢0.5 ï¹¢0.5 ï¹¢0.5 ＞50～80 ï¹¢2.0 ï¹¢2.0 ï¹¢2.2 ï¹¢2.5 ï¹¢0.5 ï¹¢0.5 ï¹¢0.5 ï¹¢0.6 ＞80 　 　 ï¹¢3.0 　 　 ï¹¢0.6

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First, calculate the cutting length per min. from the feed and spindle speed. l=f×n=.008×1000=8IPM Substitute the answer above into the formulae. Tc=lm÷l=4÷8=0.5(min) 0.5×60=30(sec) The answer is 30 sec.

Substitute f=0.2mm/rev, RE=0.8 into the formula. h=0.22÷(8×0.8)×1000=6.25µm The theoretical finished surface roughness is 6µm.

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